3x^2-280x+2500=0

Solution for 3x^2-280x+2500=0 equation:

3x^2-280x+2500=0

a = 3; b = -280; c = +2500;
Δ = b2-4ac
Δ = -2802-4·3·2500
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-220}{2*3}=\frac{60}{6}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+220}{2*3}=\frac{500}{6}
=83+1/3
$